2sin^4x+5cos^2-3=0

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Solution for 2sin^4x+5cos^2-3=0 equation:


Simplifying
2sin4x + 5cos2 + -3 = 0

Reorder the terms:
-3 + 5cos2 + 2in4sx = 0

Solving
-3 + 5cos2 + 2in4sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 5cos2 + 3 + 2in4sx = 0 + 3

Reorder the terms:
-3 + 3 + 5cos2 + 2in4sx = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 5cos2 + 2in4sx = 0 + 3
5cos2 + 2in4sx = 0 + 3

Combine like terms: 0 + 3 = 3
5cos2 + 2in4sx = 3

Add '-2in4sx' to each side of the equation.
5cos2 + 2in4sx + -2in4sx = 3 + -2in4sx

Combine like terms: 2in4sx + -2in4sx = 0
5cos2 + 0 = 3 + -2in4sx
5cos2 = 3 + -2in4sx

Divide each side by '5os2'.
c = 0.6o-1s-2 + -0.4in4o-1s-1x

Simplifying
c = 0.6o-1s-2 + -0.4in4o-1s-1x

Reorder the terms:
c = -0.4in4o-1s-1x + 0.6o-1s-2

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